鋼混答案

1、第6章習(xí)題答案章習(xí)題答案61已知一鋼筋混泥土矩形截面純扭構(gòu)件，截面尺寸bh=150mm300mm，作用于構(gòu)件上的扭矩設(shè)計值T=3.60KN.m，采用C30混泥土，采用HPB235級鋼筋。試計算其配筋量?！航狻徊楸淼茫簍f=1.43N2mmyvf=210N2mmyf=210N2mm取s?=35mmC=25mm?2263150(3)(3300150)2.81251066tbwhbmm????????42.(15050)(30050)2.51

2、0cccAbhmm???????2()2(100250)700cccubhmm??????取1.2??由公式得：4666640.351.22102.5103.6100.351.432.8125101.21.23.6100.351.432.8125100.31781.21.22.02.510yvstlttcstlstlfATfWAsAsAs????????????????????????取單肢8?即stlA?＝50.3即50.31580.

3、3178smm??取s＝150mm由縱箍比可知：2..1.221050.3700282.210150ystlyvstlcyvstlcstlyfAsfAufAuAmmfs?????????查附表11取4?10即2314stlAmm?結(jié)構(gòu)在剪扭作用下，結(jié)構(gòu)受剪及受扭箍筋最小配筋率為：.min.min0000.1.4350.30.280.190.34210100150svsvcAbs????????36601.51.50.9395.52106

4、.71010.510.5410200365ttVWTbh?????????????2(20050)(40050)52500cAmm?????受剪箍筋由公式624可得：352100.7(1.50.9395)2003651.10.21391.25210365svlvAs???????????受扭箍筋取1.3??，由公式627可得：6644100.356.7100.93951.10.10451.21.32105.2510stltAs?????

5、???????故得腹板單肢箍筋的需要量為0.21390.10450.2112stlAs???取箍筋直徑為8?（250.3svlAmm?）50.32380.2110.211svlAs???mm取s=220mm受扭縱筋：21.350.32101000210220297stlAmm??????故得腹板縱筋：彎曲受壓區(qū)縱筋總面積為22972149sAmm???選用2210(157)SAmm???彎曲受拉縱筋總面積為27332972882sAmm

6、???選用2220218(883)sAmm????配筋圖如下：71已知矩行截面柱b=300mm，h=400mm。計算長度L0為3m，作用軸向力設(shè)計值N=300KN，彎矩設(shè)計值M=150KN.m，混泥土強度等級為C20，鋼筋采用HRB335級鋼筋。設(shè)計縱向鋼筋A(yù)s及As的數(shù)量?！航狻徊楸淼茫篶f=9.6N2mmyf?=300N2mm取s?=40mm0shha??=360mm?00.5eMN??m20aemm??0520iaeeemm???