化學(xué)標(biāo)準(zhǔn)電勢表

1、標(biāo)準(zhǔn)標(biāo)準(zhǔn)電極電勢表1在酸性溶液中在酸性溶液中(298K)(298K)電對方程式E?VLi(I)－(0)Li＋＋e－＝Li－3.0401Cs(I)－(0)Cs＋＋e－＝Cs－3.026Rb(I)－(0)Rb＋＋e－＝Rb－2.98K(I)－(0)K＋＋e－＝K－2.931Ba(II)－(0)Ba2＋＋2e－＝Ba－2.912Sr(II)－(0)Sr2＋＋2e－＝Sr－2.89Ca(II)－(0)Ca2＋＋2e－＝Ca－2.868Na(I)

2、－(0)Na＋＋e－＝Na－2.71La(III)－(0)La3＋＋3e－＝La－2.379Mg(II)－(0)Mg2＋＋2e－＝Mg－2.372Ce(III)－(0)Ce3＋＋3e－＝Ce－2.336H(0)－(－I)H2(g)＋2e－＝2H－－2.23Al(III)－(0)AlF63－＋3e－＝Al＋6F－－2.069Th(IV)－(0)Th4＋＋4e－＝Th－1.899Be(II)－(0)Be2＋＋2e－＝Be－1.847U(II

3、I)－(0)U3＋＋3e－＝U－1.798Hf(IV)－(0)HfO2＋＋2H＋＋4e－＝Hf＋H2O－1.724Al(III)－(0)Al3＋＋3e－＝Al－1.662Ti(II)－(0)Ti2＋＋2e－＝Ti－1.630Zr(IV)－(0)ZrO2＋4H＋＋4e－＝Zr＋2H2O－1.553Si(IV)－(0)[SiF6]2－＋4e－＝Si＋6F－－1.24Mn(II)－(0)Mn2＋＋2e－＝Mn－1.185Cr(II)－(0)C

4、r2＋＋2e－＝Cr－0.913Ti(III)－(II)Ti3＋＋e－＝Ti2＋－0.9B(III)－(0)H3BO3＋3H＋＋3e－＝B＋3H2O－0.8698Ti(IV)－(0)TiO2＋4H＋＋4e－＝Ti＋2H2O－0.86Te(0)－(－II)Te＋2H＋＋2e－＝H2Te－0.793Zn(II)－(0)Zn2＋＋2e－＝Zn－0.7618Ta(V)－(0)Ta2O5＋10H＋＋10e－＝2Ta＋5H2O－0.750Cr(II

5、I)－(0)Cr3＋＋3e－＝Cr－0.744Nb(V)－(0)Nb2O5＋l0H＋＋10e－＝2Nb＋5H2O－0.644As(0)－(－III)As＋3H＋＋3e－＝AsH3－0.608U(IV)－(III)U4＋＋e－＝U3＋－0.607Ag(I)－(0)AgCl＋e－＝Ag＋Cl－0.22233As(III)－(0)HAsO2＋3H＋＋3e－＝As＋2H2O0.248Hg(I)－(0)Hg2Cl2＋2e－＝2Hg＋2Cl－(飽和

6、KCl)0.26808Bi(III)－(0)BiO＋＋2H＋＋3e－＝Bi＋H2O0.320U(VI)－(IV)UO22＋＋4H＋＋2e－＝U4＋＋2H2O0.327C(IV)－(III)2HCNO＋2H＋＋2e－＝(CN)2＋2H2O0.330V(IV)－(III)VO2＋＋2H＋＋e－＝V3＋＋H2O0.337Cu(II)－(0)Cu2＋＋2e－＝Cu0.3419Re(VII)－(0)ReO4－＋8H＋＋7e－＝Re＋4H2O0.3

7、68Ag(I)－(0)Ag2CrO4＋2e－＝2Ag＋CrO42－0.4470S(IV)－(0)H2SO3＋4H＋＋4e－＝S＋3H2O0.449Cu(I)－(0)Cu＋＋e－＝Cu0.521I(0)－(－I)I2＋2e－＝2I－0.5355I(0)－(－I)I3－＋2e－＝3I－0.536As(V)－(III)H3AsO4＋2H＋＋2e－＝HAsO2＋2H2O0.560Sb(V)－(III)Sb2O5＋6H＋＋4e－＝2SbO＋＋3H

8、2O0.581Te(IV)－(0)TeO2＋4H＋＋4e－＝Te＋2H2O0.593U(V)－(IV)UO2＋＋4H＋＋e－＝U4＋＋2H2O0.612Hg(II)－(I)2HgCl2＋2e－＝Hg2Cl2＋2Cl－0.63Pt(IV)－(II)[PtCl6]2－＋2e－＝[PtCl4]2－＋2Cl－0.68O(0)－(－I)O2＋2H＋＋2e－＝H2O20.695Pt(II)－(0)[PtCl4]2－＋2e－＝Pt＋4Cl－0.755

9、Se(IV)－(0)H2SeO3＋4H＋＋4e－＝Se＋3H2O0.74Fe(III)－(II)Fe3＋＋e－＝Fe2＋0.771Hg(I)－(0)Hg22＋＋2e－＝2Hg0.7973Ag(I)－(0)Ag＋＋e－＝Ag0.7996Os(VIII)－(0)OsO4＋8H＋＋8e－＝Os＋4H2O0.8N(V)－(IV)2NO3－＋4H＋＋2e－＝N2O4＋2H2O0.803Hg(II)－(0)Hg2＋＋2e－＝Hg0.851Si(IV

10、)－(0)(quartz)SiO2＋4H＋＋4e－＝Si＋2H2O0.857Cu(II)－(I)Cu2＋＋I(xiàn)－＋e－＝CuI0.86N(III)－(I)2HNO2＋4H＋＋4e－＝H2N2O2＋2H2O0.86Hg(II)－(I)2Hg2＋＋2e－＝Hg22＋0.920N(V)－(III)NO3－＋3H＋＋2e－＝HNO2＋H2O0.934Pd(II)－(0)Pd2＋＋2e－＝Pd0.951N(V)－(II)NO3－＋4H＋＋3e－＝N